  Rank: Advanced Member Groups: Registered
Joined: 13/10/2010(UTC)
Posts: 172
Location: USA
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Hello,
The calculation with units:
T1=25 C T2=0 C I1=10 A
I2:=[2^((T2-T1)/10)]*I1
I1=9.41 A
WHILE without units:
[2^((25-0)/10)]*10= 1.77
Any idea?
Thanks,
Basile
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Rank: Newbie
Groups: Registered
Joined: 05/08/2011(UTC)
Posts: 4
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it's not a bug the problem is that you are using Celsius instead of Kelvin smath work with kelvin and do (correctly): [2^(((0+273.15)-(25+273.15))/(10+273.15))]*10=9.41 because the means of the formula that you wrote is [2^(ΔT/T)]*I and work (even without smath) differently with Celsius and Kelvin this work in the same way with Celsius and Kelvin: [2^(ΔT1/ΔT2)]*I (where ΔT2 in your example may be: 10°C-0°C) (sorry for my english :blush 
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