Rank: Administration Groups: Registered, Advanced Member Joined: 23/06/2009(UTC) Posts: 1,740 Was thanked: 318 time(s) in 268 post(s)
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Hello, Just to mention something regarding this issue. I think this has some connection with it. In v0.94 you will have f(a):a*mat(b1,b2,b3,3,1)f(a)=mat(a*b1,a*b2,a*b3,3,1)f(mat(a1,a2,a3,1,3))=mat(mat(a1*b1,a2*b1,a3*b1,1,3),mat(a1*b2,a2*b2,a3*b2,1,3),mat(a1*b3,a2*b3,a3*b3,1,3),3,1)f(mat(a1,a2,a3,3,1))=mat(mat(a1,a2,a3,3,1)*b1,mat(a1,a2,a3,3,1)*b2,mat(a1,a2,a3,3,1)*b3,3,1) or f(mat(a1,a2,a3,3,1))=mat(mat(a1*b1,a2*b1,a3*b1,3,1),mat(a1*b2,a2*b2,a3*b2,3,1),mat(a1*b3,a2*b3,a3*b3,3,1),3,1)f(mat(u1,v1,z1,u2,v2,z2,u3,v3,z3,3,3))=mat(mat(u1*b1,v1*b1,z1*b1,u2*b1,v2*b1,z2*b1,u3*b1,v3*b1,z3*b1,3,3),mat(u1*b2,v1*b2,z1*b2,u2*b2,v2*b2,z2*b2,u3*b2,v3*b2,z3*b2,3,3),mat(u1*b3,v1*b3,z1*b3,u2*b3,v2*b3,z2*b3,u3*b3,v3*b3,z3*b3,3,3),3,1)In v0.95 you will have f(a):a*mat(b1,b2,b3,3,1)f(a)=a*mat(b1,b2,b3,3,1)f(mat(a1,a2,a3,1,3))=mat(a1*b1+a2*b2+a3*b3,1,1)f(mat(a1,a2,a3,3,1))=a1*b1+a2*b2+a3*b3f(mat(u1,v1,z1,u2,v2,z2,u3,v3,z3,3,3))=mat(u1*b1+v1*b2+z1*b3,u2*b1+v2*b2+z2*b3,u3*b1+v3*b2+z3*b3,3,1)I think that the situation with v0.95 is much acceptable now than before. On the other hand, I think that we have to be careful now because we can not take for granted that the result of these operation are symbolic vectors, matrices - as we would expect. Regards, Radovan Edited by user 18 June 2012 14:46:23(UTC)
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