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Function pol2xy does not work correctly
  Rank: Member Groups: Registered
Joined: 08/03/2012(UTC) Posts: 25  Location: Prague, Dolní Chabry Was thanked: 3 time(s) in 2 post(s)
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Hello. The function pol2xy(r;fi) works only if the Options/Answer is set to Auto, or Standard. And it returns a complex result !! regards Olik   Edited by user 13 March 2012 00:58:33(UTC)
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  Rank: Administration Groups: Registered, Advanced Member Joined: 23/06/2009(UTC) Posts: 1,740   Was thanked: 318 time(s) in 268 post(s)
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Hello, The only answer I can give you is that you can ignore the imaginary parts of the results (rather small values). a:asin(3/5)pol2xy(5,a)=sys(4-2.01761263306198*10^{-15}*i,3+3.13994492395312*10^{-15}*i,2,1)Re(pol2xy(5,a))=sys(4,3,2,1)el(Re(pol2xy(5,a)),1)=4el(Re(pol2xy(5,a)),2)=3Regards, Radovan Edited by user 12 March 2012 14:31:16(UTC)
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When Sisyphus climbed to the top of a hill, they said: "Wrong boulder!" |
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Rank: Member Groups: Registered
Joined: 08/03/2012(UTC) Posts: 25 Location: Prague, Dolní Chabry Was thanked: 3 time(s) in 2 post(s)
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Hello.  Also we can simply use the definition formulas: x:= r.cos(α)
y:= r.sin(α)& it works even for Option/Answer set to "Real". (for Answer=Complex you will get two results for x = -4, 4 ... -4 is imho wrong) [ we can solve this by using the function eval . . . a:=eval(asin(3/5)) ] But the funcion pol2xy() does not work correctly - this is the essence of my bug report. regards Olik btw: I do not see the difference betwen the Option Answer = auto/standard What is the difference? Edited by user 19 March 2012 18:40:54(UTC)
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Function pol2xy does not work correctly
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