What to use in Smath studio to simplify irrational expression

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What to use in Smath studio to simplify irrational expression

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Deni		#1 Posted : 04 November 2010 01:17:18(UTC)
Rank: Newbie Groups: Registered Joined: 04/11/2010(UTC) Posts: 2 Location: Macedonia		Here is the expression that I've been trying to simplify "a" and "b" are not suposed to be defined. Every time I put that expression in and put equals on the end, it says "a is not defined" wherein there is way to simplify this expression with no "a" or "b" given (not on computer), but i don't know how to do it in SMath Studio. Also if there is a way, could it show a step-by-step simplifying of the expression. Thanks for the help in advance. Deni


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omorr		#2 Posted : 04 November 2010 10:23:59(UTC)
Rank: Administration Groups: Registered, Advanced Member Joined: 23/06/2009(UTC) Posts: 1,740 Was thanked: 318 time(s) in 268 post(s)		Hello Deni, Deni wrote: Here is the expression that I've been trying to simplify "a" and "b" are not suposed to be defined. Every time I put that expression in and put equals on the end, it says "a is not defined" wherein there is way to simplify this expression with no "a" or "b" given (not on computer), but i don't know how to do it in SMath Studio When you use the numerical equal to "=" everything in the given expression must be defined (have their numerical values). Therefore, you can not calculate the value of the above expression if the variables "a" and "b" do not have their values. Regarding the simplification of the given expression - you can do two things at the moment. 1. Select a part of an expression and choose Calculation=>Simplify. Below that expression you will have the simplified part of the expression (in the way SMath symbolic engine is doing this). For instance if you select the Denominator and choose Calculation=>Simplify you will get this: {sqrt(a-/{sqrt(a+-sqrt(a-}-{a-b}/sqrt(a^2-b^2-a+}/sqrt({a^2}/{b^2}-1) sqrt(a-sqrt(a+(1/{b^2})^{1/2} 2. If you select the entire expression or use symbolic equal to "->", you will get this: {sqrt(a-/{sqrt(a+-sqrt(a-}-{a-b}/sqrt(a^2-b^2-a+}/sqrt({a^2}/{b^2}-1)—{sqrt(a(-1+a)+b(1-)-(sqrt(a+-sqrt(a-)sqrt(a-}/{sqrt(a+sqrt(a(-1+a)+b(1-)(sqrt(a+-sqrt(a-)(1/{b^2})^{1/2}} Regards, Radovan
		When Sisyphus climbed to the top of a hill, they said: "Wrong boulder!"
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Deni		#3 Posted : 04 November 2010 20:53:09(UTC)
Rank: Newbie Groups: Registered Joined: 04/11/2010(UTC) Posts: 2 Location: Macedonia		That was a very useful explanation, a big Thank you Radovan, I appreciate it very much.


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omorr		#4 Posted : 04 November 2010 21:11:12(UTC)
Rank: Administration Groups: Registered, Advanced Member Joined: 23/06/2009(UTC) Posts: 1,740 Was thanked: 318 time(s) in 268 post(s)		You are welcome Enjoy using SMath. Regards, Radovan
		When Sisyphus climbed to the top of a hill, they said: "Wrong boulder!"
		WWW

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