Rank: Advanced Member Groups: Registered
Joined: 23/12/2012(UTC) Posts: 94 Was thanked: 169 time(s) in 132 post(s)
|
Originally Posted by: Razonar Hi Ioan. As first comment, now I see that you use L as the length of the rigid catenary, meanwhile I use it as length of the elastic one. Also, I'm not sure about the parameter E, if it is in kN, kN/m or kN/m^2. Usually, one identify the parameters by its units, but the differential equation can have some units inconsistencies, derived from the convention that parametric curves have not units. For instance, I don't know if assign the unit meter to the curve parameter p, which is more consistent with the units in the ODE...
Hi Alvaro,
Thanks for your feedback.
I feel useful to add some explanations concerning my developments because I recognize that it is poorly documented.
In my work I try to satisfy two antagonisms: i) That of Engineering – to affect information with units – this is magnificently served by Smath; ii) That of Mathematics, where it is preferable to avoid units, as much as possible.
An example of my practice is here:
First formula is a classic Strength of Materials one, with units inside. In the second formula, I operated some transformations, targeting to avoid units inside the integral, making it so more robust.
As for input information, I used only 3 (H;V;L) data for inextensible cable and I added 3 (w; A; E) data for the elastic cable; they are: A = area of the cable section (Surface units); w = uniform vertical load along the cable line (Force / Length); E = elasticity (Young) modulus (units Force/Surface).
Best regards, Ioan
|
Do to others as you would like them to do to you! Knowledge is of no value unless you put it into practice - Chekhov |
|
|
|
Forum Jump
You cannot post new topics in this forum.
You cannot reply to topics in this forum.
You cannot delete your posts in this forum.
You cannot edit your posts in this forum.
You cannot create polls in this forum.
You cannot vote in polls in this forum.