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BUG? defining function with "if" and plotting
Rank: Administration Groups: Registered, Advanced Member Joined: 23/06/2009(UTC) Posts: 1,740 Was thanked: 318 time(s) in 268 post(s)
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Please look at the picture: When the function is defined with "if" then it can not be plotted together with the matrix M (M - not defined??). Bug, I suppose? Regards, Radovan P.S. Andrey, I think you've sent me recently some pictures with "if" defined functions. As I remember, plotting of those functions has been resolved. Might this be connected? Edited by user 09 October 2009 04:30:15(UTC)
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When Sisyphus climbed to the top of a hill, they said: "Wrong boulder!" |
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Rank: Administration Groups: Registered, Advanced Member Joined: 23/06/2009(UTC) Posts: 1,740 Was thanked: 318 time(s) in 268 post(s)
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Hello, Considering the plotting functions (defined with "if" ) and two-column matrices here is a continued discussion about that. It seems that the "if" will not work but the function defined via relation operation will work. Here is the picture The two plots should be basically the same. Here the plot on the right is Ok, and on the left is not working. Pay attention that the plotting has been fixed in v0.85_3578 (see here ) The same problem will be wrong in v0.85_3545 BTW, it seems that the integration of noncontinous functions will work when defined with relational operators (see the example) Regards Radovan |
When Sisyphus climbed to the top of a hill, they said: "Wrong boulder!" |
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BUG? defining function with "if" and plotting
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