Hi SMath team,

how to plot a polar diagram of radiated fields of infinitesimal linear wire?
Could you plase help me with this topic.

Bes regards,
Andrey

Please see you the file Herzt_Dipole_Polarediagram.sm (329kb) downloaded 16 time(s).

Hi Martin. After I post several images in very poor resolution I think the best option is to capture the images in SMath with the zoom set to 70% or something similar to obtain decent images.

Best regards.
Alvaro.

Hello Smath users,

do you have experience or any idea, who to create a polar plot like Mathcad, as shown on the picture?
I need a dB or Log - scale for radius and marking of directions

Thank you for you help.

Best regards,
Andrey

Dear SMath users and developers,

unfortunately I did not succeed to create the graph as polar diagram with the help of Maple plugin.
I have tried different options, with Maxima plugin it works, with Maple unfortunately not.

Just one thing. How can I create the polar lines and circular lines (dB or Log20 or Log10) with different step sizes?
A desirable is the one polar diagram as on the picture Calculation of the corner antenna.sm (424kb) downloaded 7 time(s).



That is unfortunately a pity that there is not available a Polar-Diagram set s a normal tool or plugin.

Best regards,
Andrey

Something like this, but you need to display the logarithm of the curve.



XYPlot. Shapes. Polar grid.sm (35kb) downloaded 19 time(s).

Спасибо, Вячеслав, это именно то, что мне было нужно.

С наилучшими пожеланиями,
Андрей

Добрый вечер Вячеслав,
мне все еще нужно обратиться к вам за помощью с Log-Polar Plot.
Я столкнулся с проблемой, как сделать полярный график с логарифмической шкалой для Theta.
Я всегда вижу отрицательное значение r в начале и в конце спискса.
Мне пришлось провести нормализацию и проверки амплитуды на отрицательный радиус перед взятием логарифма, но это не помогло.



Как по Вашему, что может быть причиной такого поведения для графика по углу Theta?

Calculation of the corner antenna_2.sm (500kb) downloaded 14 time(s).

Спасибо, Андрей

Можно так.

Edited by user 22 November 2021 02:52:02(UTC)  | Reason: Not specified

There is there a very mysterious r> 0.01. My explanation is that, first of all, you have to make sure that the argument for log10 is positive, but then you have to verify that in the polar graph it is f> 0, because in polar coordinates only positive values of the position vector module are considered. This implies that f = 0.5 * log10 (r) +1> 0 is needed, from which solving for r we have the mysterious condition r> 0.01.

Best regards.
Alvaro.

Addendum:

The original range for the graph is 0 < theta < 180º . Outside of that domain the problem is not defined, or simply does not matter. Viacheslav restricted the domain by imposing y> 0, which is correct, but the following form shows a little more clearly how the transformation of coordinates from Cartesian to logarithmic polar is done, and then imposing the original condition on the domain, so that XY plot just plot in the desired range.

Edited by user 23 November 2021 19:52:07(UTC)  | Reason: Addendum