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Offline sleschke  
#1 Posted : 10 February 2009 20:39:01(UTC)
sleschke


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Hello Smath,

is there a way of solving a complete system of equations?

Lets say I have a set of 10 equations with 10 variables
and I am looking for the vector of values for the 10 variables
so that all 10 equations are true.
The equations may be nonlinear, contain all kinds of arithmetic expressions
and complex values.

Is this already possible, or will it be implemented in a future version?

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Offline Andrey Ivashov  
#2 Posted : 10 February 2009 21:42:42(UTC)
Andrey Ivashov


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I was ready to answer something like: system of the linear equations you can solve with matrices, f.e.:

But it was before you said:
sleschke wrote:
The equations may be nonlinear, contain all kinds of arithmetic expressions
and complex values.

So, the result answer is: implementation of this feature will be the one of the next steps...
Offline omorr  
#3 Posted : 23 June 2009 17:49:42(UTC)
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There is "solve" for a single equation. I could see on the Side panel under "Functions" that there is a "Equation systems" template (v.08).
Could you please explain in short how does it work?

Best Regards
When Sisyphus climbed to the top of a hill, they said: "Wrong boulder!"
Offline Andrey Ivashov  
#4 Posted : 23 June 2009 19:47:27(UTC)
Andrey Ivashov


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Hello, omorr.
omorr wrote:
There is "solve" for a single equation. I could see on the Side panel under "Functions" that there is a "Equation systems" template (v.08).
Could you please explain in short how does it work?

"Equation systems" template created not for solving sets of equations, it was created to work with +/- and -/+ operators. Here is example below:
Open in SMath Cloud
Also you can work with that construction as a specific array:
Open in SMath Cloud
Offline omorr  
#5 Posted : 23 June 2009 22:23:43(UTC)
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Thanks for the explanation.

As soon as posted I realised that I missed the point.

I should have played a bit more with SMath first, sorry.

Regards,
Radovan
When Sisyphus climbed to the top of a hill, they said: "Wrong boulder!"
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