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Method A.B. Draghilev and animation spatial mechanisms - Ber7 Options  Email this topic  Watch this topic  Print this topic » Normal Threaded

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Ber7		#21 Posted : 03 August 2016 00:36:54(UTC)
Rank: Advanced Member Groups: Registered Joined: 15/07/2010(UTC) Posts: 437 Location: Beer-Sheva Was thanked: 520 time(s) in 288 post(s)		Jean Giraud ,here it is your animation without the display on the 2D graf 3d.sm (447kb) downloaded 49 time(s).
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CBG		#22 Posted : 03 August 2016 02:53:06(UTC)
Rank: Advanced Member Groups: Registered Joined: 14/10/2015(UTC) Posts: 305 Was thanked: 76 time(s) in 57 post(s)		Hello Jean , It would be better to put the animation in a 3/4 view . Would that be possible? Best Regard Carlos
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Jean Giraud		#23 Posted : 04 August 2016 01:40:10(UTC)
Rank: Guest Groups: Registered Joined: 04/07/2015(UTC) Posts: 6,800 Was thanked: 975 time(s) in 803 post(s)		Originally Posted by: CBG Hello Jean , It would be better to put the animation in a 3/4 view . Would that be possible? Best Regard Carlos Hello Carlos, "3/4 view" : like setting TV screen 3/4 or other style. You could scale the vertical vector, it would end being hugly. The x, y ranges in the CreateMesh have these limits under the hood. These limits are what make the Breather so pleasant like the Eiffel shape. Attached the 4 fixed orientations. Jean Rotate Breather [4 Orientations].sm (18kb) downloaded 45 time(s).
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CBG		#24 Posted : 04 August 2016 19:19:20(UTC)
Rank: Advanced Member Groups: Registered Joined: 14/10/2015(UTC) Posts: 305 Was thanked: 76 time(s) in 57 post(s)		Hello Jean. Excellent !!! But the file does not work for me, it indicates that M is not defined. Besides, I can not update the Maple plugin . On the other hand , Is it possible to see a 3/4 view from the Z axis?, I think it will better. Thank you. Carlos
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Ber7		#25 Posted : 25 July 2017 12:47:08(UTC)
Rank: Advanced Member Groups: Registered Joined: 15/07/2010(UTC) Posts: 437 Location: Beer-Sheva Was thanked: 520 time(s) in 288 post(s)		Spherical four-bar mechanism Axis joints intersect at the center of the sphere 3d1.smz (98kb) downloaded 44 time(s).
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Ber7		#26 Posted : 23 January 2022 22:25:21(UTC)
Rank: Advanced Member Groups: Registered Joined: 15/07/2010(UTC) Posts: 437 Location: Beer-Sheva Was thanked: 520 time(s) in 288 post(s)		Puma manipulator The working body of the manipulator moves along a given trajectory. To solve the problem, 5 equations with six unknowns were used. -Two link length equations -Equations of the condition that the links are in the same plane -Two space curve equations Puma.sm (35kb) downloaded 25 time(s). Edited by user 13 March 2022 08:20:14(UTC)  | Reason: Not specified
4 users thanked Ber7 for this useful post.		on 24/01/2022(UTC),  on 24/01/2022(UTC),  on 24/01/2022(UTC),  on 24/01/2022(UTC)
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Ber7		#27 Posted : 31 January 2022 00:57:50(UTC)
Rank: Advanced Member Groups: Registered Joined: 15/07/2010(UTC) Posts: 437 Location: Beer-Sheva Was thanked: 520 time(s) in 288 post(s)		The Schatz mechanism https://espace.curtin.edu.au/bit...JMES_author_draft_02.pdf The Schatz mechanism provides a perfect dynamic balance оf both centripetal and centrifugal forces as patented in 1971 as the only widely-used overconstrained linkages in industry, mainly used as spatial mixing-machines. Shatz 2cikla.sm (129kb) downloaded 11 time(s). Edited by user 13 March 2022 08:37:09(UTC)  | Reason: Not specified
1 user thanked Ber7 for this useful post.		on 31/01/2022(UTC)
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grelkin2		#28 Posted : 09 March 2022 23:10:10(UTC)
Rank: Member Groups: Registered Joined: 12/12/2020(UTC) Posts: 12		Originally Posted by: Ber7 Puma manipulator The working body of the manipulator moves along a given trajectory. To solve the problem, 5 equations with six unknowns were used. -Two link length equations -Equations of the condition that the links are in the same plane -Two space curve equations In my option this system have Rigid link between 2 points 2 equations about belonging 2 points to the same sphere x2*y1-y2*x1 some sin curve Don't quite understand about x2*y1-y2*x1. Some spherical meaning? The difference between azimuth angles is not perfect equal. Replace with atan(y1/x1)-atan(y2/x2) to make perfect equal.
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Ber7		#29 Posted : 10 March 2022 08:23:43(UTC)
Rank: Advanced Member Groups: Registered Joined: 15/07/2010(UTC) Posts: 437 Location: Beer-Sheva Was thanked: 520 time(s) in 288 post(s)		Originally Posted by: grelkin2 In my option this system have Hi grelkin2. Please provide your equations so that the solutions can be compared. Best regards
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grelkin2		#30 Posted : 10 March 2022 22:07:49(UTC)
Rank: Member Groups: Registered Joined: 12/12/2020(UTC) Posts: 12		Hmm, atan is expensive function, may be switching to spherical coordinate reduces number of steps initial vector 1.5355 0.8065 0.9959 1.9127 0.5761 0.0989 precision 1e-3 sphere(1,0,0,0) sphere(2,0,0,0) line(1,2) atan(x[1]/x[0])-atan(x[4]/x[3]) .5*sin(8*x[3]+9*x[4])-x[5]
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grelkin2		#31 Posted : 15 March 2022 07:33:50(UTC)
Rank: Member Groups: Registered Joined: 12/12/2020(UTC) Posts: 12		Originally Posted by: Ber7 The Schatz mechanism The Schatz mechanism provides a perfect dynamic balance оf both centripetal and centrifugal forces as patented in 1971 as the only widely-used overconstrained linkages in industry, mainly used as spatial mixing-machines. It has equation four points are coplanar Maxima gives me this equation is exactly is zero with any coordinate
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Ber7		#32 Posted : 17 March 2022 21:50:15(UTC)
Rank: Advanced Member Groups: Registered Joined: 15/07/2010(UTC) Posts: 437 Location: Beer-Sheva Was thanked: 520 time(s) in 288 post(s)		The Schatz mechanism. Modernized animation. Schatz Linkage.sm (144kb) downloaded 23 time(s).
2 users thanked Ber7 for this useful post.		on 18/03/2022(UTC),  on 18/03/2022(UTC)
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алексей_алексей		#33 Posted : 24 March 2022 20:32:51(UTC)
Rank: Advanced Member Groups: Registered Joined: 30/09/2012(UTC) Posts: 33 Was thanked: 10 time(s) in 5 post(s)		In the Schatz mechanism, the length of the middle link does not change, and the axes of the middle link are constantly perpendicular to each other. In this case, one vertical rack (input link) rotates uniformly. This is for those who are interested. And Draghilev's method does not directly work in this case.
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Ber7		#34 Posted : 24 March 2022 23:12:58(UTC)
Rank: Advanced Member Groups: Registered Joined: 15/07/2010(UTC) Posts: 437 Location: Beer-Sheva Was thanked: 520 time(s) in 288 post(s)		The error of changing the length of the middle link is ε = 10^{-7} You can also check the perpendicularity of the hinges Proverka.sm (48kb) downloaded 17 time(s). Edited by user 24 March 2022 23:17:23(UTC)  | Reason: Not specified
1 user thanked Ber7 for this useful post.		on 13/04/2022(UTC)
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grelkin2		#35 Posted : 12 April 2022 02:33:46(UTC)
Rank: Member Groups: Registered Joined: 12/12/2020(UTC) Posts: 12		To @Ber7, @алексей_алексей Not really understand Schatz system Please correct me if I'm wrong AO=const, BO'=const, AB=const С extra point, AC=CB Still two equation, one as I understand Z1*Z2=const? and the last one is Normals to planes ABO and ABO' must be perpendicular? Magenta lines are normal vectors to ABO and ABO' Pause and check perpendicularity Rotate the view to get best observation Make animation in mov format for the best quality, If not working, message me Animation schatz.mov (286kb) downloaded 8 time(s).
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Ber7		#36 Posted : 13 April 2022 17:37:22(UTC)
Rank: Advanced Member Groups: Registered Joined: 15/07/2010(UTC) Posts: 437 Location: Beer-Sheva Was thanked: 520 time(s) in 288 post(s)		Please, read the article at the link post # 27.The length of each link is equal to one, and the distance between the vertical axes is equal to the root of 3.Equation x3*x6 = 1/2 derived from Equation (6) of this paper. "Normals to planes ABO and ABO' must be perpendicular?" Yes. Regards
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grelkin2		#37 Posted : 13 April 2022 20:39:49(UTC)
Rank: Member Groups: Registered Joined: 12/12/2020(UTC) Posts: 12		sinθ_2*sinθ_5=const θ_2, θ_5 rotating angles around the ZA2, ZB2 rotating axis, difficult equation You cann't use any intial values for coordinates because ABO and ABO' must be perpendicular, if you fixed all coordinates but one, you've got Quadratic equation. If you have no real roots change others coordinates and try again. Also you can change equation to be cos(α)=const, α≠90, α is angle between normals
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