 Rank: Newbie
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Joined: 09/09/2010(UTC)
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Location: San Diego
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I want to do the following:
length := 16 in
diameter := trunc(((length + 2 in)/pi)in)
diameter = 7.0000 in
I need to be able to set the result of a parenthesis-enclosed
expression
to inch units, then apply the trunc() function to
it, retaining the units as inches. At the moment, it
seems as though it is only possible to apply the trunc()
function to the results of computation in parenthesis
using SI units, so the result becomes 0 because the
value of (length + 2 in)/pi is 0.1779 m.
The workaround seems to be to not use units at all,
but that is not nearly as nice.
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  Rank: Administration Groups: Registered, Advanced Member Joined: 23/06/2009(UTC) Posts: 1,740   Was thanked: 318 time(s) in 268 post(s)
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Hello, What about this  The argument inside "trunc" divide by the desired unit (in - in this case). Then, the entire expression multiply by the desired unit (in - in this case) In general, when you do not want SI units - divide the expression by the desired unit. Then you will get the dimensionless number with the value in the desired unit. Regards, Radovan Edited by user 09 September 2010 11:43:59(UTC)
| Reason: Not specified |
When Sisyphus climbed to the top of a hill, they said: "Wrong boulder!" |
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Rank: Newbie
Groups: Registered
Joined: 09/09/2010(UTC)
Posts: 4
Location: San Diego
Was thanked: 2 time(s) in 1 post(s)
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This worked well. Thank you!
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