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Offline Jean Giraud  
#1 Posted : 22 April 2016 02:35:32(UTC)
Jean Giraud

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By same token of "Pipe Data", Colebrook Moody has been refactored.
Observe carefully the code to make the 'solve block' survive by
introducing it within a program structure. In this implicit solve,
the block needs an [one] initial value. Same code structure as
it was discovered in Mathcad 8/11 [undocumented].
A splendid piece of Engineering work for publishing and documenting
the project, tracable for the client's archive.

Jean

Forum Colebrook Pipe Data.gif


Inst_Colebrook MOODY.sm (17kb) downloaded 62 time(s).

Inst_Colebrook Pipe Data.sm (25kb) downloaded 60 time(s).

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Offline mikekaganski  
#2 Posted : 22 April 2016 03:13:44(UTC)
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kW/hr is non-existent (physically nonsensical) unit of power. Power is measured in kW, and work is measured in kW*hr.
Best regards,
Mike Kaganski
Offline Jean Giraud  
#3 Posted : 23 April 2016 07:25:50(UTC)
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Originally Posted by: mikekaganski Go to Quoted Post
kW/hr is non-existent (physically nonsensical) unit of power


Interesting: that's what alll Canadians we pay for 'kWh' consummed.
Billing may vary from Provinces to Provinces
Here is my billing for february 2016
"690 Kwh @ $ 0.0965/kWh"
My kW/hr is user to conform Q[T/hr] to deconfuse unit user confused.

Jean


Offline Jean Giraud  
#4 Posted : 23 April 2016 07:32:22(UTC)
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... typos, updated, on-fly calculator added.

Jean Inst_Colebrook Pipe Data.sm (61kb) downloaded 43 time(s).
Offline mikekaganski  
#5 Posted : 23 April 2016 09:36:54(UTC)
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Originally Posted by: Jean Giraud Go to Quoted Post
Interesting: that's what alll Canadians we pay for 'kWh' consummed.
Billing may vary from Provinces to Provinces
Here is my billing for february 2016
"690 Kwh @ $ 0.0965/kWh"
My kW/hr is user to conform Q[T/hr] to deconfuse unit user confused.

Yes. kWh = kW*hr. This is unit of energy. Energy is integral of power by time, i.e. mean power multiplied by time. Power is measuted in kiloWatts, time in hours.
Best regards,
Mike Kaganski
Offline Jean Giraud  
#6 Posted : 23 April 2016 15:43:20(UTC)
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Originally Posted by: mikekaganski Go to Quoted Post
Yes. kWh = kW*hr. This is unit of energy. Energy is integral of power by time, i.e. mean power multiplied by time. Power is measuted in kiloWatts, time in hours.


What you say is right, but not for design Engineer.
The Engineer wants to know the "POWER RATING" of the
motor to push Q[T/hr] via the pump it activates.
That's what the "Pipe Data" answers for those in that stuff.
Just introduce the 'r' efficiency factor from the supplier
of the 'MotorPump'.

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