 Rank: Newbie
Groups: Registered
Joined: 02/06/2010(UTC) Posts: 6   Location: Italy Was thanked: 1 time(s) in 1 post(s)
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I desire to solve this:
c:12-1,23*(1+x/2)
solve(c;x)=17,512195
I get the value of x, but if I write
c:12-1,23*(1+x/3)
solve(c;x)=
I get the message "no real roots" (in this case the value of x is 26,268292)
Someone can help me to understand why?
Stefano
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  Rank: Advanced Member Groups: Registered
Joined: 09/01/2010(UTC) Posts: 102  Location: Oregon, USA Was thanked: 5 time(s) in 5 post(s)
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Stefano, Try using the solve function with 4 arguments, where the third and fourth arguments are the lower and upper bounds respectively within which the root may be found. See screenshot below:  Graphing the function can help in choosing a suitable interval for the lower and upper bounds. Please see the following thread and wiki page for more info: Solve not workingSolve functionBTW: An improved solve function would be a great plugin project for someone to work on.  erisive: Maybe someday. Edited by user 11 June 2010 04:13:48(UTC)
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Will Massie
Mechanical Engineer
Oregon, USA |
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Rank: Newbie
Groups: Registered
Joined: 02/06/2010(UTC) Posts: 6 Location: Italy Was thanked: 1 time(s) in 1 post(s)
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Thank you Maweilian, before posting my question I read only this post http://en.smath.info/for....aspx?g=posts&t=434, so I supposed that the need for an interval was only for non linear equation. I read carefully the posts you linked in your answer and now I understood the behaviour of solve function. Thank you again. Stefano
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